worksheet for Problem set 3,
January 30, 2006
1.
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FOIL method
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redundancy in Punnett squares
2.
DO NOT get used to
convention. ALWAYS read the problem!!
3.
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When labeling a
pedigree, choose letters in which the uppercase and lowercase look very different
from one another. Aa Bb Gg
are good choices. Ss Cc Tt are not.
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When dealing
with a rare trait like the dread disease “hobbit-toe”, if it is not CLEAR from
the pedigree, you may assume that those that marry into an afflicted family are
not affected and do not carry the trait.
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the
multiplication rule
4.
For a family that has 3 children,
there are 4 possibilities
♀♀♀
♀♀♂
♀♂♂
♂♂♂
However, ORDER is important!
There are ultimately 8 possible outcomes
♀♀♀
♀♀♂ ♀♂♀ ♂♀♀
♀♂♂ ♂♀♂ ♂♂♀
♂♂♂
each condition above has a
(1/2)(1/2)(1/2)=1/8=0.125 probability of occurring.
Probabilities always sum to
one, e.g. 8 x 0.125=1
Thus, the probability of
having one boy is 3 x 0.125= 0.375
Shortcut
p=Pr(event A)
q=Pr(event B)
n=# of trials
s=# of times A happens
t=# of times B happens